The gas inside of a container exerts $42 P a$ $42 Pa$ of pressure and is at a temperature of $420^{o} K$ $420 ^o K$ . If the pressure in the container changes to $72 P a$ $72 Pa$ with no change in the container's volume, what is the new temperature of the gas?

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The gas inside of a container exerts $42 P a$ $42 Pa$ of pressure and is at a temperature of $420^{o} K$ $420 ^o K$ . If the pressure in the container changes to $72 P a$ $72 Pa$ with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2018-04-25T20:40:33

$final temperature is 720^{o} K$ $"final temperature is "720 ^o K$

Explanation:

$As the volume of the container does not change, the increase of$ $"As the volume of the container does not change, the increase of"$
$the gas pressure causes the temperature to increase.$ $"the gas pressure causes the temperature to increase."$

$We need to use the Gay-Lussac law to find the temperature.$ $"We need to use the Gay-Lussac law to find the temperature."$

$P_{i} = 42 P a (initial pressure of the gas)$ $P_i=42 Pa("initial pressure of the gas")$
$P_{f} = 72 P a (final pressure of the gas)$ $P_f=72 Pa("final pressure of the gas")$
$T_{1} = 420^{o} K (initial temperature of the gas)$ $T_1=420 ^o K("initial temperature of the gas")$
$T_{f} = ? (final temperature of the gas)$ $T_f=?("final temperature of the gas")$

$\frac{P_{i}}{T_{i}} = \frac{P_{f}}{T_{f}}$ $P_i/T_i=P_f/T_f$

$cancel(42)/cancel(420)=72/T_f$

$"let's divide both numerator and denominator by 42 "$

$1/10=72/T_f$

$1*T_f=72*10$

$T_f=720 ^oK$

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The gas inside of a container exerts $42 P a$ $42 Pa$ of pressure and is at a temperature of $420^{o} K$ $420 ^o K$ . If the pressure in the container changes to $72 P a$ $72 Pa$ with no change in the container's volume, what is the new temperature of the gas?

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Explanation:

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The gas inside of a container exerts 42 Pa42Pa42 Pa of pressure and is at a temperature of 420 ^o K420oK420 ^o K. If the pressure in the container changes to 72 Pa72Pa72 Pa with no change in the container's volume, what is the new temperature of the gas?

1 Answer

Explanation:

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The gas inside of a container exerts $42 P a$ $42 Pa$ of pressure and is at a temperature of $420^{o} K$ $420 ^o K$ . If the pressure in the container changes to $72 P a$ $72 Pa$ with no change in the container's volume, what is the new temperature of the gas?