How do you solve #x + 2 = sqrt(7 x) + 2#?

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Answer 1 · 2018-04-26T05:20:55

#x=0# and #x=7#

#x+2=sqrt(7x)+2#

Subtract 2 on both sides

#=> x=sqrt(7x)#

Square Both Sides

#x^2=7x#

divide by #x# on both sides (assuming #x != 0#)

#=> x=7#

However, we must check if #x=0# is a solution

#0+2=sqrt(7*0)+2#

#=> 2=0+2#

This is true, so #x=0# is a solution!

Thus, #x=0# and #x=7#