How do you write an equation of a line given (12, 0), m=3/4?

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Answer 1 · 2018-04-26T23:34:46

$y = \frac{3}{4} x - 9$ $y =3/4x-9$

Since we are provided the slope and a point on the line we can use the equation for point slope form of the equation of a line.

$y - y_{1} = m (x - x_{1})$ $y-y_1 =m(x-x_1)$

Where $m =$ $m=$ slope and the point is $(x_{1}, y_{1})$ $(x_1,y_1)$

For this situation $m = \frac{3}{4}$ $m=3/4$ and a point of $(12, 0)$ $(12,0)$

$m = \frac{3}{4}$ $m=3/4$
$x_{1} = 12$ $x_1=12$
$y_{1} = 0$ $y_1=0$

$y - y_{1} = m (x - x_{1})$ $y-y_1 =m(x-x_1)$

Plug in the values
$y - 0 = \frac{3}{4} (x - 12)$ $y-0 =3/4(x-12)$

Use distributive property to eliminate the parenthesis
$y = \frac{3}{4} x - 9$ $y =3/4x-9$