What is the derivative of #(x)/sqrt(x^2-4)#?

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Answer 1 · 2018-05-04T00:45:19

The answer #1/sqrt(x^2-4)-(x^2)/(x^2-4)^(3/2)#

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#(x)/sqrt(x^2-4)#

we can rewrite it

#x*(x^2-4)^(-1/2)#

now we will derivate it

#d/dx[x*(x^2-4)^(-1/2)]=x*(-1/2)(x^2-4)^(-3/2)*(2x)+(x^2-4)^(-1/2)*1#

#1/sqrt(x^2-4)-(x^2)/(x^2-4)^(3/2)#