A container with a volume of $6 L$ $6 L$ contains a gas with a temperature of $650 K$ $650 K$ . If the temperature of the gas changes to $350 K$ $350 K$ without any change in pressure, what must the container's new volume be?

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A container with a volume of $6 L$ $6 L$ contains a gas with a temperature of $650 K$ $650 K$ . If the temperature of the gas changes to $350 K$ $350 K$ without any change in pressure, what must the container's new volume be?

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Answer 1 · 2018-05-08T18:52:32

You can use Charles' Law for this:

$V_{1} (T_{2}) = V_{2} (T_{1})$ $V_1(T_2) = V_2(T_1)$

Find your values:

$V_{1}$ $V_1$ = $6$ $6$ liters
$V_{2}$ $V_2$ = $?$ $?$
$T_{1}$ $T_1$ = $650$ $650$ K
$T_{2}$ $T_2$ = $350$ $350$ K

and plug them in:

$6 (350) = V_{2} (650)$ $6(350) = V_2(650)$

Multiply $6$ $6$ and $350$ $350$ to get $2100$ $2100$ , which gets you to

$2100 = V_{2} (650)$ $2100 = V_2(650)$

Divide both sides by $650$ $650$ to get $V_{2}$ $V_2$ by itself:

$\frac{2100}{650} = 3.2308$ $2100/650 = color(red)(3.2308)$

And that's your final answer. The container's new volume must be $3.2308$ $3.2308$ liters.

Note that if the temperature were in Fahrenheit or Celsius you would have to convert to Rankine or Kelvin, respectively - as Charles' Law only works with an absolute temperature scale. However, since the given temperatures were in Kelvin, no such conversion is necessary.

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A container with a volume of $6 L$ $6 L$ contains a gas with a temperature of $650 K$ $650 K$ . If the temperature of the gas changes to $350 K$ $350 K$ without any change in pressure, what must the container's new volume be?

1 Answer

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A container with a volume of 6L6 L contains a gas with a temperature of 650K650 K. If the temperature of the gas changes to 350K350 K without any change in pressure, what must the container's new volume be?

1 Answer

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Impact of this question

A container with a volume of $6 L$ $6 L$ contains a gas with a temperature of $650 K$ $650 K$ . If the temperature of the gas changes to $350 K$ $350 K$ without any change in pressure, what must the container's new volume be?