Question

What is `(cot2theta)/3` in terms of `tantheta`?

Answer 1

`(1 - tan^2 t)/(6tan t)`

Explanation:

Trig identity:
`tan 2t = (2tan t)/(1 - tan^2 t)`
Take the inverse -->
`cot 2t = 1/(tan 2t) = (1 - tan^2 t)/(2tan t)`
`(cot 2t)/3 = (1 - tan^2 t)/(6tan t)`