Question

How do you add or subtract `(3/x) + (13)/(x – 11)`?

Answer 1

`(3/x) + 13/(x-11)` = `(16x-33)/(x(x-11)`

Explanation:

By treating this expression same as normal fraction adding and subtracting:

`(3/x) + 13/(x-11)rarr` common denominator will be `x xx (x-11)`

`(3/x) + 13/(x-11)` = `(3(x-11) + 13x)/(x(x-11))`

`(3/x) + 13/(x-11)` = `(3x-33+13x)/(x(x-11))`

`(3/x) + 13/(x-11)` = `(16x-33)/(x(x-11)`