How much power is produced if a voltage of #2 V# is applied to a circuit with a resistance of #16 Omega#?

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Answer 1 · 2018-05-22T09:59:48

#"0.25 W"#

We know that

#"electric power"# #= "voltage" xx "current"#

Given:

According to Ohm's Law,

# V=IR#

#:. I = V/R#

So

#I = "2 V"/(16 \ Omega) =1/8 \ "A"#

Therefore,

#P=VI#

#P = "2 V" * 1/8 \"A"#

#P = 1/4 \ "W" = "0.25 W"#