How do you evaluate $f (- 3)$ $f(-3)$ given $f (x) = 4 x^{3} + x^{2} - 5 x$ $f(x)=4x^3+x^2-5x$ ?

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How do you evaluate $f (- 3)$ $f(-3)$ given $f (x) = 4 x^{3} + x^{2} - 5 x$ $f(x)=4x^3+x^2-5x$ ?

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Answer 1 · 2018-05-23T06:26:33

$= - 84$ $= -84$

Explanation:

$f (x) = 4 x^{3} + x^{2} - 5 x$ $f(x) = 4x^3 + x^2 - 5x$
$f (- 3)$ $f(-3)$
Therefore,
$f (- 3) = 4 {(- 3)}^{3} + {(- 3)}^{2} - 5 (- 3)$ $f(-3) = 4(-3)^3 + (-3)^2 - 5(-3)$
$= - 84$ $= -84$

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How do you evaluate $f (- 3)$ $f(-3)$ given $f (x) = 4 x^{3} + x^{2} - 5 x$ $f(x)=4x^3+x^2-5x$ ?

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Explanation:

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How do you evaluate $f (- 3)$ $f(-3)$ given $f (x) = 4 x^{3} + x^{2} - 5 x$ $f(x)=4x^3+x^2-5x$ ?