If a projectile is shot at an angle of $\frac{π}{2}$ $pi/2$ and at a velocity of $31 \frac{m}{s}$ $31 m/s$ , when will it reach its maximum height??

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Answer 1 · 2018-06-07T15:04:22

$3.2 s$ $"3.2 s"$

Time taken to reach maximum height is given by

$T = \frac{usinθ}{g}$ $"T" = "usinθ"/"g"$

$T = \frac{31 m/s \times sin(π/2)}{{9.8 m/s}^{2}}$ $color(white)("T") = "31 m/s × sin(π/2)"/"9.8 m/s"^2$

$color(white)("T") = 3.2\ "s"$

If a projectile is shot at an angle of pi/2π2pi/2 and at a velocity of 31 m/s31ms31 m/s, when will it reach its maximum height??