How do you express the complex number in trigonometric form: $6$ ?

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Answer 1 · 2018-06-08T08:01:09

See explanation.

The number $6$ lies on a positive part of real axis, so the angle is $0$ and the module is $6$ , so the trigonometric form of $6$ is:

$6=6*(cos0^o + isin0^o)$