It is easily shown, that, as xx gets smaller, x^2x2 gets smaller at an even greater rate, so 1/x^21x2 will be greater.
A few steps:
x=1->x^2=1->1/x^2=1x=1→x2=1→1x2=1
x=1/2->x^2=1/4->1/x^2=4x=12→x2=14→1x2=4
x=1/100->x^2=10000->1/x^2=10000x=1100→x2=10000→1x2=10000
This means that the closer xx goes to 00 the higher the function goes. In this case it doesn't matter whether x->0x→0 from the positive side or from the negative, as the square makes it al positive. By choosing smaller and smaller values of xx, the function can reach any size you want.
Translated to "the language":
lim_(x->0^+) 1/x^2=lim_(x->0^-) 1/x^2=lim_(x->0) 1/x^2= oo
graph{1/x^2 [-17.75, 18.3, -1.61, 16.42]}
