What is the vertex form of #y=7x^2-14x-6 #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Bill Jorgensen Jun 16, 2018 #y=7(x-2)^2-13# Explanation: #y=7x^2-14x-6# #y+6=7x^2-14x# #y+6=7(x^2-2x)# #y+6 + 7c=7(x^2-2x+c)# #c=(-2/2)^2= 1# #y+6 + 7*1=7(x^2-2x+1)# #y+13=7(x-2)^2# #y=7(x-2)^2-13# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 2642 views around the world You can reuse this answer Creative Commons License