How do you solve #k^2-6k+8=0# by completing the square?
2 Answers
Jun 16, 2018
Explanation:
#"subtract 8 from both sides"#
#k^2-6k=-8#
#k^2+2(-3)k color(red)(+9)=-8color(red)(+9)#
#(k-3)^2=1#
#color(blue)"take square root of both sides"#
#k-3=+-1larrcolor(blue)"note plus or minus"#
#k=3+-1#
#k=3-1=2" or "k=3+1=4#
Jun 16, 2018
Explanation:
First lets complete the square: