What is the chemical equation for the formation of HF from the single, isolated H and F atoms?

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Answer 1 · 2018-06-19T01:38:46

The formation of $HF$ $"HF"$ from single, isolated $H$ $"H"$ and $F$ $"F"$ atoms can be explained using standard enthalpy change of formation.

Under standard conditions, hydrogen and fluorine exist in diatomic gaseous state, $H_{2}$ $"H"_2$ and $F_{2}$ $"F"_2$ respectively.

By forming an equation, we can see the formation of $HF$ $"HF"$ .

$H_{2} + F_{2} \to HF$ $"H"_2+"F"_2 -> "HF"$

Now, all we need to do is balance the equation.

$\frac{1}{2} H_{2} + \frac{1}{2} F_{2} \to HF$ $1/2 "H"_2 + 1/2 "F"_2 -> "HF"$

OR

$H_{2} + F_{2} \to 2 HF$ $"H"_2 + "F"_2 -> 2"HF"$