How do you solve $sqrtv = 2$ and find any extraneous solutions?

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Answer 1 · 2018-06-21T18:32:38

$v=4$

It is sufficient to square both sides of the equation to get

$v = 4$

It is not an extraneous solution, since if we plug it in the equation we get

$sqrt(4)=2$

which indeed works.

How do you solve sqrtv = 2sqrtv = 2 and find any extraneous solutions?