What is the area of a triangle with sides of length 4, 2, and 1?

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Answer 1 · 2018-06-22T16:49:29

This is not possible to solve in real number solutions #RR# because it is not possible to have a triangle with sides: #4,2,1#

#(isqrt(105))/4#

To solve in the imaginary realm use Heron's formula:

#Area=sqrt(s(s-a)(s-b)(s-c))#

where #s=(a+b+c)/2# which is the #"perimeter"/2#

sides are #4,2,1#

#s=(4+2+1)/2=7/2#

#A=sqrt(7/2(7/2-4)(7/2-2)(7/2-1))=(isqrt(105))/4#