How do you solve the triangle given #triangleABC, a=8, mangleB=35, mangleC=55#?

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Answer 1 · 2018-06-25T12:21:48

See below

We know
#a=8#
#hatB=35#
#hatC=55#

Then however #hatA+hatB+hatC=180# then #hatA=90#

ABC is a right triangle

By #sin# theorem #a/sinA=b/sinB# or #8/1=b/sin35# then

#b=8·sin35=4.5886#

And again with leg c: #c/sin55=8/sin90# and #c=8·sin55=6.5532#

Or by Pitagorean theorem #8^2=4.5886^2+c^2#