How do you simplify $- 2 w b \times {(4 w)}^{2}$ $-2wb×(4w)^2$ ?

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Answer 1 · 2018-06-26T01:59:17

Simplify ${(4 w)}^{2}$ $(4w)^2$ to $16 w^{2}$ $16w^2$ and multiply. Remember that $a^{b} \cdot a^{c} = a^{b + c}$ $a^b*a^c=a^(b+c)$ :

$- 2 w b \cdot 16 w^{2}$ $-2wb*16w^2$
$(- 2 \cdot 16) (w^{1} \cdot w^{2}) (b)$ $(-2*16)(w^1*w^2)(b)$
$- 32 w^{3} b$ $-32w^3b$

Hope this helped!

How do you simplify −2wb×(4w)2-2wb×(4w)^2?