Question

How do you solve `x^2 + 2xy + 3y^2` for x = 70 & y = 4?

Answer 1

The answer is `5,508`.

Explanation:

`x^2 + 2xy + 3y^2`

For

• `x=70`
• `y=4`

Substitute the values given for `x` and `y` in the equation

`( 70)^2 + 2( 70)(4)+ 3( 4 )^2`

`=4900 + 560 + 48`

`= 5,508`