What is the value of $\frac{3 x + 8 y}{x - 2 y}$ $(3x+8y)/(x-2y)$ if $\frac{x}{2 y} = 2$ $x/(2y)=2$ ?

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Answer 1 · 2015-03-24T09:25:15

The answer is: $10$ $10$ .

Since $\frac{x}{2 y} = 2$ $x/(2y)=2$ than $x = 4 y$ $x=4y$ ,

so:

$\frac{3 \cdot (4 y) + 8 y}{4 y - 2 y} = \frac{12 y + 8 y}{2 y} = \frac{20 y}{2 y} = 10$ $(3*(4y)+8y)/(4y-2y)=(12y+8y)/(2y)=(20y)/(2y)=10$ .

What is the value of (3x+8y)/(x-2y)3x+8yx−2y(3x+8y)/(x-2y) if x/(2y)=2x2y=2x/(2y)=2?