How do you solve $log 4 x = 2$ $log 4x = 2$ ?

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Answer 1 · 2018-06-26T14:34:14

Rewrite in in exponential form!

Note that logarithms with a base of 10 ( ${log}_{10} x$ $log_10 x$ ) are commonly rewritten without it ( $log x$ $logx$ ).

${log}_{a} b = x$ $log_a b=x$ is the same as $a^{x} = b$ $a^x=b$ . Let's apply this to our equation:

${log}_{10} 4 x = 2$ $log_10 4x=2$
$10^{2} = 4 x$ $10^2=4x$
$100 = 4 x$ $100=4x$
$25 = x$ $25=x$

Hope this helped!

Answer 2 · 2018-06-26T14:36:11

x = 25

$log (4 x) = 2$ $log(4x)= 2$
Since the base is not mentioned we assume it to be 10.
$4 x = 10^{2}$ $4x=10^2$
$x = \frac{100}{4} = 25$ $x=100/4=25$

How do you solve log4x=2log 4x = 2?