How do you find all zeros of the function #f(x)=(x+5)^3(x-4)(x+1)^2#?

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Answer 1 · 2018-07-06T14:34:55

#color(blue)(x=-5,x=-5,x=-5 , x=4, x=-1#

We first equate #(x+5)^3(x-4)(x+1)# to zero:

#(x+5)(x+5)(x+5)(x-4)(x+1)=0#

We just find values of x that make each bracket in turn zero.

Solutions here are:

#x=-5,x=-5,x=-5 , x=4, x=-1#

The graph confirms this:

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