Question

What is the vertex form of `y=1/5x^2-4/7x+3/5`?

Answer 1

`y=1/5(x-10/7)^2+47/245`

Explanation:

`1/5x^2-4/7x+3/5`
`=1/5(x^2-20/7x)+3/5`
`=1/5(x^2-20/7x+(20/7divide2)^2-(20/7divide2)^2)+3/5`
`=1/5(x-10/7)^2-1/5*100/49+3/5`
`=1/5(x-10/7)^2+(3*49-100)/(5*49)`
`=1/5(x-10/7)^2+47/245`