How do you solve $log_2(2x)=log_2 100$ ?

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Answer 1 · 2018-07-12T15:28:35

$color(blue)(x=50)$

If:

$log_a(b)=log_a(c)=>b=c$

Hence:

$log_2(2x)=log_2(100)$

$2x=100=>x=100/2=50$

Answer 2 · 2018-07-12T22:07:27

$x=50$

Since our bases are the same, we can essentially cancel them out and be left with

$2x=100$

By dividing both sides by $2$ , this easily simplifies to

$x=50$

Hope this helps!

How do you solve log_2(2x)=log_2 100log_2(2x)=log_2 100?