How do you solve # 5⋅18^6x= 26#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Roy Ø. Jul 26, 2018 #x=13/(45*18^5)# Explanation: #5*18^6x=26# Factorise #26=2*13# Divide each side with #5*18*18^5=5*2*9*18^5# This gives #x=(2*13)/(2*5*9*18^5)# =#13/(45*18^5)# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1737 views around the world You can reuse this answer Creative Commons License