How do you solve #log_4 z + log_4 8 = log_4 24#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer sankarankalyanam Jul 29, 2018 #color(red)(z = 3# Explanation: #log a + log b = log (ab), " Log rule"# #log_4 z + log_4 8 = log_4 24# #log_4(8 z) = log_4 24# #:. 8 z = 24, " as base same"# #color(red)(z = 24/8 = 3# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2057 views around the world You can reuse this answer Creative Commons License