A container has a volume of $12 L$ $12 L$ and holds $8 m o l$ $8 mol$ of gas. If the container is compressed such that its new volume is $4 L$ $4 L$ , how many moles of gas must be released from the container to maintain a constant temperature and pressure?

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Answer 1 · 2018-08-02T17:54:52

The number of moles to be released is $= 5.33 m o l$ $=5.33mol$

Apply Avogadro's Law

$\frac{Volume}{Number of moles} = Constant$ $"Volume"/"Number of moles"= " Constant"$

At constant temperature and pressure

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$ $V_1/n_1=V_2/n_2$

The initial volume is $= 12 L$ $=12L$

The initial number of moles is $n_{1} = 8 m o l$ $n_1=8mol$

The final volume is $V_{2} = 4 L$ $V_2=4L$

The final number of moles is

$n_{2} = \frac{V_{2}}{V_{1}} \cdot n_{1} = \frac{4}{12} \cdot 8 = \frac{8}{3} m o l$ $n_2=V_2/V_1*n_1=4/12*8=8/3mol$

The number of moles to be released is

$= n_{2} - n_{1} = 8 - \frac{8}{3} = \frac{16}{3} = 5.33 m o l$ $=n_2-n_1=8-8/3=16/3=5.33mol$

A container has a volume of 12L12 L and holds 8mol8 mol of gas. If the container is compressed such that its new volume is 4L4 L, how many moles of gas must be released from the container to maintain a constant temperature and pressure?