How do you solve the triangle when B = 22.6 degrees, b = 5.55 cm and a = 13.8 cm?

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Answer 1 · 2018-08-03T09:30:39

#(sin A)/a=(sin B)/b#

#(sin A)/13.8=(sin 22.6)/5.55#

#sin A=13.8xx((sin 22.6)/5.55)#

#sin A=0.9555451267#

A=72.85176328, A=72.9 (1 dp)

B=22.6, A=72.9 so C=84.5

#c/(sin C)=b/(sin B)#

#c/(sin 84.5)=5.55/(sin 22.6)#

#c=sin 84.5xx(5.55/(sin 22.6))#

c=14.3755299, c=14.4 cm (1dp)