A 21.5L sample of gas at 107kPa has a temperature of 27.20C. What is the pressure of the gas if it is transferred to a 32.6L container at 44.10C?

1 Answer

P_2 ~~ "74.5 kPa"

Explanation:

Use

PV=nRT

where n and R stay constant during the transfer.

nR=(PV)/(T)

so

[P_1V_1]/(T_1) = [P_2V_2]/(T_2)

or

P_2=[P_1V_1T_2]/(V_2T_1)

Don't forget that

T = θ+273.15

So

P_2 = ("107 kPa" * "21.5 L" * (44.10 + 273.15)\ "K")/("32.6 L" * (27.20 + 273.15) \ "K")

P_2 ~~ "74.5 kPa"