What is the area of a triangle with sides of length 2, 4, and 5?

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Answer 1 · 2018-08-04T17:04:36

Area is #3.8# square units

If three sides of a triangle are #a,b# and #c#, then

its area is #sqrt(s(s-a)(s-b)(s-c))#, where #s=(a+b+c)/2#

Here sides are #2,4# and #5# and hence #s=(2+4+5)/2=11/2#

and area of triangle is

#sqrt(11/2(11/2-2)(11/2-4)(11/2-5))#

= #sqrt(11/2xx7/2xx3/2xx1/2)#

= #1/4sqrt231=15.19868/4=3.79967# or say #3.8#