How do you solve # log_3(47) = log_8(x)#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Shwetank Mauria Aug 7, 2018 #x=1462.514# Explanation: As #log_3 47=log_8x#, we have #log47/log3=logx/log8# or #logx=log47/log3xxlog8# or #logx=16721/0.4771xx0.9031=3.1651# and #x=10^3.1651=1462.514# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1537 views around the world You can reuse this answer Creative Commons License