How do you solve #13^(3x)-1=91#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Narad T. Aug 8, 2018 The solution is #=0.59# Explanation: The equation is #13^(3x)-1=91# #=>#, #13^(3x)=91+1=92# Taking logs on both sides #ln(13^(3x))=ln(92)# #3xln(13)=ln(92)# #x=(ln92)/(3*ln13)=0.59# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2231 views around the world You can reuse this answer Creative Commons License