A container has a volume of $6 L$ $6 L$ and holds $5 m o l$ $5 mol$ of gas. If the container is compressed such that its new volume is $12 L$ $12 L$ , how many moles of gas must be released to maintain a constant temperature and pressure?

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Answer 1 · 2018-08-08T08:55:49

As the question is written, the number of moles can only be added is $= 5 m o l$ $=5mol$

Apply Avogadro's Law

$\frac{Volume}{Number of moles} = Constant$ $"Volume"/"Number of moles"= " Constant"$

At constant temperature and pressure

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$ $V_1/n_1=V_2/n_2$

The initial volume is $= 6 L$ $=6L$

The initial number of moles is $n_{1} = 5 m o l$ $n_1=5mol$

The final volume is $V_{2} = 12 L$ $V_2=12L$

This is not a compression, it's an expansion

The final number of moles is

$n_{2} = \frac{V_{2}}{V_{1}} \cdot n_{1} = \frac{12}{6} \cdot 5 = 10 m o l$ $n_2=V_2/V_1*n_1=12/6*5=10mol$

The number of moles to be added is

$= n_{2} - n_{1} = 10 - 5 = 5 m o l$ $=n_2-n_1=10-5=5mol$

A container has a volume of 6L6 L and holds 5mol5 mol of gas. If the container is compressed such that its new volume is 12L12 L, how many moles of gas must be released to maintain a constant temperature and pressure?