How do you solve #-3 sqrt(3x) = -5#?

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Answer 1 · 2015-08-06T06:22:09

#color(blue)(x=25/27#

#-3sqrt(3x) = -5#

Squaring both sides

#(-3sqrt(3x))^2 = (-5)^2#

#9 * 3x = 25#

#27x = 25#

#color(blue)(x=25/27#

Answer 2 · 2018-08-10T03:01:52

#x=25/27#

Let's start by dividing both sides by #-3# to get

#sqrt(3x)=5/3#

To get rid of the radical, we can square both sides to get

#3x=25/9#

We can multiply both sides by #1/3# to isolate #x# to get

#x=25/27#

Hope this helps!