A projectile is shot from the ground at a velocity of $27 m/s$ at an angle of $(5pi)/12$ . How long will it take for the projectile to land?

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Answer 1 · 2018-08-11T05:35:31

The time to land is $=5.32s$

Resolving in the vertical direction and applying the equation of motion

$s=ut+1/2at^2$

The distance travelled is $s=0$

The initial velocity is $u=27sin(5/12pi)$

The acceleration due to gravity is $a=g=9.8ms^-2$

$27sin(5/12pi)*t-1/2*9.8*t^2=0$

$t=0$ which is the initial conditions

$t=(27sin(5/12pi))/(4.9)=5.32s$

A projectile is shot from the ground at a velocity of 27 m/s27 m/s at an angle of (5pi)/12(5pi)/12. How long will it take for the projectile to land?