Power Series and Limits
Key Questions
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To be honest, I would not use power series on this one since this is a perfect problem to demonstrate the application of Squeeze Theorem. Here is how:
We know
#-1 le sinx le 1# #Rightarrow -3 le 3sinx le 3# #Rightarrow -3/e^x le {3sinx}/e^x le 3/e^x# .Since
#lim_{x to infty}(-3/e^x)=-3/infty=0# and
#lim_{x to infty}3/e^x=3/infty=0# ,we conclude that
#lim_{x to infty}{3sinx}/e^x=0# by Squeeze Theorem.
I hope that this was helpful.
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Here is a simple application of a power series in evaluating a limit.
#lim_{x to 0}{sinx]/x# by replacing
#sinx# by its Maclaurin series.#=lim_{x to 0}{x-x^3/{3!}+x^5/{5!}-x^7/{7!}+cdots}/{x}# by distributing the division to each term,
#=lim_{x to 0}(1-x^2/{3!}+x^4/{5!}-x^6/{7!}+cdots)# by sending
#x# to zero,#=1-0+0-0+cdots# since all but the first term are zero,
#=1#
I hope that this was helpful.
Questions
Power Series
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Introduction to Power Series
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Differentiating and Integrating Power Series
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Constructing a Taylor Series
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Constructing a Maclaurin Series
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Lagrange Form of the Remainder Term in a Taylor Series
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Determining the Radius and Interval of Convergence for a Power Series
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Applications of Power Series
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Power Series Representations of Functions
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Power Series and Exact Values of Numerical Series
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Power Series and Estimation of Integrals
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Power Series and Limits
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Product of Power Series
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Binomial Series
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Power Series Solutions of Differential Equations