How do you calculate the heat required to melt 15 kg of silver?

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Answer 1 · 2014-04-16T00:13:42

You multiply the mass of the silver by its heat of fusion.

The heat of fusion ( $ΔH_("fus")$ ) is the amount of heat required to melt a unit mass of a solid.

$q = mΔH_("fus")$ , where $q$ is the amount of heat and $m$ is the mass of the sample.

The heat of fusion of silver is 111 kJ/kg, so

$q = mΔH_("fus")$ = 15 kg × $(111" kJ")/(1" kg")$ = 1700 kJ