Question #dfb1a

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Question #dfb1a

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Answer 1 · 2015-01-26T23:38:52

The molar absorptivity of molecule X is given by $ε = 4.5 \times 10^{3} M^{- 1} c m^{- 1}$ $epsilon=4.5xx10^3M^(-1)cm^(-1)$

The Beer - Lambert Law states:

$A = ε l c$ $A=epsilonlc$

$A$ $A$ = absorbance

$l$ $l$ = path length in cm

$c$ $c$ = molar concentration

$ε$ $epsilon$ = molar absorptivity

Rearranging gives:

$ε = \frac{A}{l c}$ $epsilon=(A)/(lc)$

$ε = \frac{0.350}{0.850 \times 90 \times 10^{- 6}} = 4.5 \times 10^{- 3} M^{- 1} c m^{- 1}$ $epsilon=(0.350)/(0.850xx90xx10^(-6)) = 4.5xx10^(-3) M^-1cm^-1$

Note I converted $μ M$ $muM$ to $M$ $M$ by multiplying by $10^{- 6}$ $10^-6$

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