Question #2567f

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Answer 1 · 2015-06-27T15:37:50

24.5m

To get the height the ball reaches above the plaza we can use:

#s=ut+1/2"g"t^(2)#

It will take 4/2 = 2s to reach its zenith.

#"g"=-9.8"m/s"#

#s=19.6xx2+1/2"g"2^(2)#

#=39.2-19.6=19.6"m"#

We can get the total distance the ball falls using:

#S_("tot")=1/2"g"t^(2)#

This time #"g"=+9.8"m/s"#

and the total time = #2+1 = 3s#

#S_("tot")=1/2"g"9=(9"g")/2#

If the height of the tower is #h# then:

#19.6+h=(9"g")/(2)#

#h=44.1-19.6=24.5"m"#