Question

Question #2f8d7

Answer 1

The wavelength should decrease by `9 1/11%`

Explanation:

Assuming the velocity of wave propagation remains constant.

Then
`color(white)("XXXX")v=w*f` is a constant
where `v` is the velocity, `w` is the wavelength, and `f` is the frequency

If `w` is increased by `10%` giving new wavelength, `hatw=1.1*w`
then we will need a new frequency `hatf`

`color(white)("XXXX")w*f = hatw*hatf = 1.1w*hatf`

`rArrcolor(white)("XXXX")hatf=1/1.1f =10/11f`

`rArrcolor(white)("XXXX")f- 10/11f = 1/11f` decrease

`1/11 = 9.090909...%`