Question

Question #3134c

Answer 1

Point of inflexion is at x=2

Explanation:

First find y'= `-xe^-x + e^-x`

Next find y" = `xe^-x - e^-x -e^-x`

= `(x-2)e^-x`

Equate the second derivative to 0. It works out x=2

Inflexion point is at x=2