Question #05d7b

↳Redirected from "An electron in a hydrogen atom drops from energy level n=5 to n=3. What is the energy transition using the Rydberg equation?"
1 Answer
Gió
Nov 18, 2015

I found: #E=4xx10^-19J#

Explanation:

You could use Einstein's equation:
#E=h*nu#
where:
#h="Planck's constant"=6.63xx10^-34Js#
#nu="frquency"=c/lambda="speed of light"/"wavelength"=#
#=(3xx10^8)/(500xx10^-9)=6xx10^14Hz#
So energy will be:
#E=6.63xx10^-34*6xx10^14=3.97xx10^-19J~~4xx10^-19J#

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