Question

568 cm3 of chlorine at 25° C will occupy what volume at -25° C while the pressure remains constant?

Answer 1

The chlorine will occupy 473 cm³.

This is a Charles' Law Problem. You can read about Charles' Law at

http://socratic.org/questions/what-is-the-relationship-between-temperature-and-volume-in-charles-law

In your question,

`V_1` = 568 cm³; `T_1` = (25 + 273.15) K = 298 K

`V_2` = ?; `T_2` = (-25 + 273.15) K = 248 K

`V_2 = V_1× T_2/T_1` = 568 cm³ ×`(248"K")/(298"K")` = 473 cm³

This makes sense. The final Kelvin temperature was about one-sixth lower than the initial temperature. The final volume should be about one-sixth (100 cm³) less than the initial volume.

Hope this helps.