Question

Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. To what temperature should it be raised to occupy a volume of 6.5 liters?

Answer 1

884.5 K

Explanation:

1) Convert 40 °C to Kelvin and you get 273 + 40 = 313 K .At this temperature the volume of the gas is 2.3 L.

2) At Temperature `T_2` Kelvin ,this temperature the volume of the gas is 6.5 L.

Remember that you have to plug into the equation in a very specific way. The temperatures and volumes come in connected pairs and you must put them in the proper place.

Using Charles law equation;

`V_1` / `T_1` = `V_2` / `T_2`

`V_1` = 2.3 L , `T_1` = 313 K

`V_2` = 6.5 L , `T_2` = ?

plug in the values;

2.3 L / 313 K = 6.5 L / `T_2`

Cross-multiply and divide:

2.3 L x (`T_2`) = 6.5 L x 313 K

2.3 L x (`T_2`) = 2034.5 L K

`T_2` = 2034.5 LK / 2.3 L

`T_2` = 884.5 K