Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. To what temperature should it be raised to occupy a volume of 6.5 liters?

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Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. To what temperature should it be raised to occupy a volume of 6.5 liters?

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Answer 1 · 2014-06-27T22:45:40

884.5 K

Explanation:

1) Convert 40 °C to Kelvin and you get 273 + 40 = 313 K .At this temperature the volume of the gas is 2.3 L.

2) At Temperature $T_{2}$ $T_2$ Kelvin ,this temperature the volume of the gas is 6.5 L.

Remember that you have to plug into the equation in a very specific way. The temperatures and volumes come in connected pairs and you must put them in the proper place.

Using Charles law equation;

$V_{1}$ $V_1$ / $T_{1}$ $T_1$ = $V_{2}$ $V_2$ / $T_{2}$ $T_2$

$V_{1}$ $V_1$ = 2.3 L , $T_{1}$ $T_1$ = 313 K

$V_{2}$ $V_2$ = 6.5 L , $T_{2}$ $T_2$ = ?

plug in the values;

2.3 L / 313 K = 6.5 L / $T_{2}$ $T_2$

Cross-multiply and divide:

2.3 L x ( $T_{2}$ $T_2$ ) = 6.5 L x 313 K

2.3 L x ( $T_{2}$ $T_2$ ) = 2034.5 L K

$T_{2}$ $T_2$ = 2034.5 LK / 2.3 L

$T_{2}$ $T_2$ = 884.5 K

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Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. To what temperature should it be raised to occupy a volume of 6.5 liters?

1 Answer

Explanation:

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