Question #e4173

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Answer 1 · 2017-04-30T18:50:48

The current gain is $beta = 49$

Given: $I_0/I_E =0.98" [1]"$

We know that the output current is the current gain $beta$ multiplied by the base current:

$I_0 = betaI_b" [2]"$

We know that the emitter current is the output current plus the base current:

$I_E = I_0+ I_b$

$I_E = betaI_b+ I_b" [3]"$

Substitute equations [2] and [3] into equation [1]:

$(betaI_b)/(betaI_b+I_b) = 0.98$

$beta/(beta+1) = 0.98$

$1 -1/(beta+1) = 0.98$

beta+1 = -1/(0.98-1)

$beta+1 = 50$

$beta = 49$