Question

Question #bc8e6

Answer 1

The beanbag that is thrown at an angle.....

Explanation:

Firstly, we need to consider velocity in the vertical direction. If we define u as the initial speed of both bean bags, then
a) the vertical velocity of the bean bag thrown straight up is `u`
b) the vertical velocity of the bean bag thrown at an angle is `u* cos50^0`
We know that acceleration is `-g`, acceleration due to gravity (negative since acting in the opposite direction to the vertical velocity),
We can now use following definition of acceleration :

`a=("final velocity"-"initial velocity")/t`

At the maximum height, the final vertical velocity will be nil, so

`a=-9.8= "-initial velocity" /t`
and so
`t="initial velocity"/9.8`

For a) `t=u/9.8`

For b) `t=u/9.8*cos50^0=u/9.8*0.64`

So (b), the bean bag thrown at an angle , will have a shorter flight time and will hit the ground first