Question #c7a86

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Answer 1 · 2016-11-28T17:55:27

The answer is #=2^(2x)#

#S(x)=x^2#

#P(x)=2^x#

#SoP(x)=S(P(x))=S(2^x)=(2^x)^2=2^(2x)#

#PoS(x)=P(S(x))=P(x^2)=2^(x^2)#

#SoP(x)!=PoS(x)#

Answer 2 · 2016-11-28T17:55:51

# :. (S@P)(y) = 4^y #

#(S@P)(y)# means the composite #S(p(y))#

# :. (S@P)(y) = S(P(y)) #
# :. (S@P)(y) = S(2^y) #
# :. (S@P)(y) = (2^y)^2 #
# :. (S@P)(y) = 2^(2y) #
# :. (S@P)(y) = 4^y #