What is the concentration of 1.12*L1.12⋅L of carbon dioxide gas?

1 Answer
anor277
Apr 25, 2016

Approx. 0.9*mol*L^-10.9⋅mol⋅L−1

Explanation:

CaCO_3(s) + 2HCl(aq) rarr CaCl_2(aq) + H_2O(l) + CO_2(g)uarrCaCO3(s)+2HCl(aq)→CaCl2(aq)+H2O(l)+CO2(g)↑⏐

We assume that the gas was collected at 298*K298⋅K and at 11 atmatm pressure. Under these conditions, 11 molmol of gas, any gas, has a volume of 25.4*L25.4⋅L

So moles of CO_2CO2 == (1.12*cancelL)/(25.4*cancelL*mol^-1) = 4.41xx10^-2*mol

Now form the stoichiometric equation, for each mole of gas produced, there were 2 mole of hydrochloric acid.

Thus "Concentration" = (2xx4.41xx10^-2*mol)/(0.100*L) = ??*mol*L^-1

This is a slight over estimate in that the gas collected is saturated with water vapour. This saturated vapour pressure should be subtracted from the pressure.

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