In a 0.250*mol*L^-1 solution, what molar quantity is associated with a 0.200*L volume?

1 Answer
Apr 24, 2016

n_"solute" = 0.05*mol

Explanation:

"Concentration" = "Moles of solute"/"Volume of solution (L)".

Thus, "Moles of solute" = "Concentration "xx" Volume".

= 0.250*mol*cancel(L^-1)xx0.200*cancel(L) = 0.0500*mol.